Calculate the time required to heat 20 kg of water from 100C to 350C using an immersion heater rated 1000 W. Assume that 80% of the power input is used to heat the water. Specific heat capacity of water = 4200 J/Kg  k

Let us consider the required time is t. power of the immersion heater is 1000W, 80% power is used only so used power = 1000*80/100 = 800W. work done by the immersion heater due to this power is W = P*t = 800t this is the form of electrical energy this energy will be used to heat the water so Heat give by the Heater = Heater taken by the water 800t = ms(T2 T1) 800t = 20*4200*[(273+35)  (273+10)] we have added 273 because we will take temp. in kelvin 800t = 20*4200*25 by solving this t = 2625 sec. 
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